[8602] 2015-01-19_破解之美:利用ECB加密缺陷突破cookie加密

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最后更新:2025-01-17
2015-01-19_破解之美:利用ECB加密缺陷突破cookie加密 E C B c o o k i e F r e e B u f   2 0 1 5 - 0 1 - 1 9 W E B c o o k i e c o o k i e c o o k i e M D 5 C B C N S T R T 使 使 E C B c o o k i e N S T R T E C B 0 x 1   E C B E C B 使 使 E C B ( E l e c t r o n i c   C o d e B o o k ) E C B E C B E C B 使 使 E C B 使 E C B 使 E C B 0 x 2   E C B 使 E C B 使 E C B c o o k i e c o o k i e 使 E C B b a s e 6 4 E C B 8 E C B [ h w 3 ]   a d m i n E C B a d m i n t e s t 1 t e s t 2 p a s s w o r d c o o k i e t e s t 1 c o o k i e : a u t h = v H M Q % 2 F N q 9 C 3 M H T 8 Z k G e M r 4 w % 3 D % 3 D
t e s t 2 c o o k i e : a u t h = M h % 2 B J M H 1 O M h c H T 8 Z k G e M r 4 w % 3 D % 3 D c o o k i e b a s e 6 4 r u b y t e s t 1 : x B C s x 1 0 x F C x D A x B D v s a O x C 6 d x 1 9 x E 3 + x E 3 t e s t 2 :   2 x 1 F x 8 9 0 } N 2 x 1 7 a O x C 6 d x 1 9 x E 3 + x E 3 a O x C 6 d x 1 9 x E 3 + x E 3   E C B c o o k i e a d m i n   a a a a   a a a a   a a a a   a a a a   a a a a c o o k i e a u t h = G k z S M 2 v K H d c a T N I z a 8 o d 1 w S 2 8 i n R H i C 2 G k z S M 2 v K H d c a T N I z a 8 o d 1 y s 9 6 E X m i r n 5 x 1 A L x D 2 3 k x C A x 1 D x D 7 x 1 A L x D 2 3 k x C A x 1 D x D 7 x 0 4 x B 6 x F 2 ) x D 1 x 1 E x B 6 x 1 A L x D 2 3 k x C A x 1 D x D 7 x 1 A L x D 2 3 k x C A x 1 D x D 7 + = x E 8 E x E 6 x 8 A x B 9 x F 9 c o o k i e x 1 A L x D 2 3 k x C A x 1 D x D 7 a a a a a a a a E C B a a a a a a a a   a d m i n 8 a a d m i n c o o k i e a u t h = G k z S M 2 v K H d e N f d X Z w r P F 0 A % 3 D % 3 D c o o k i e
x 1 A L x D 2 3 k x C A x 1 D x D 7 a a a a a a a a a a a a a a a a a a a a c o o k i e a a a a a a a a 8 E C B x 1 A L x D 2 3 k x C A x 1 D x D 7 a d m i n x 8 D } x D 5 x D 9 x C 2 x B 3 x C 5 x D 0   b a s e 6 4 c o o k i e a d m i n 0 x 3   E C B E C B C B C C B C S S L I P S E C N S T R T T R T t r t 9 1 7 [ / N S T R T F r e e B u f ]
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