[13586] 2018-12-28_挖洞经验用跨站搜索在谷歌问题跟踪平台实现敏感信息获取

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最后更新:2025-01-18
2018-12-28_挖洞经验用跨站搜索在谷歌问题跟踪平台实现敏感信息获取   |   c l o u d s   F r e e B u f   2 0 1 8 - 1 2 - 2 8 M o n o r a i l h t t p s : / / b u g s . c h r o m i u m . o r g /   X S - S e a r c h   a t t a c k M o n o r a i l   M o n o r a i l C h r o m i u m I s s u e   T r a c k e r A C L M o n o r a i l C h r o m i u m M o n o r a i l A n g l e P D F i u m G e r r i t ,   V 8     t h e   A l l i a n c e   f o r   O p e n   M e d i a P r o j e c t   Z e r o 使 M o n o r a i l
M o n o r a i l C S V 使 M o n o r a i l h t t p s : / / b u g s . c h r o m i u m . o r g / p / c h r o m i u m / i d 9 1 1 3 7 4 9 1 1 3 7 5 C S V h t t p s : / / b u g s . c h r o m i u m . o r g / p / c h r o m i u m / i s s u e s / c s v ? c a n = 1 & q = i d % 3 A 9 1 1 3 7 4 % 2 C 9 1 1 3 7 5 & c o l s p e c = I D C S V A d v a n c e d   S e a r c h R e s t r i c t - V i e w - S e c u r i t y T e a m p e r m i s s i o n   s e c u r i t y t e a m   n e e d e d   t o   u s e   v i e w   C S R F 访 访 C S V
q = R e s t r i c t = V i e w - S e c u r i t y T e a m h t t p s : / / b u g s . c h r o m i u m . o r g / p / c h r o m i u m / i s s u e s / c s v ? c a n = 1 & q = R e s t r i c t = V i e w - S e c u r i t y T e a m & c o l s p e c = I D C S R F q = R e s t r i c t = V i e w - S e c u r i t y T e a m   i d 8 9 5 7 3 5 8 7 7 3 4 7 8 7 0 5 7 3 C S V 使 c o l s p e c = I D + S u m m a r y + S u m m a r y + S u m m a r y h t t p s : / / b u g s . c h r o m i u m . o r g / p / c h r o m i u m / i s s u e s / c s v ? c a n = 1 & q = i d : 5 1 3 3 7 & c o l s p e c = I D + S u m m a r y + S u m m a r y + S u m m a r y C S V 3 S u m m a r y 1 S u m m a r y
X S - S e a r c h   A t t a c k X S - S e a r c h   A t t a c k X S - T i m i n g   A t t a c k   o n   s e a r c h   s e r v i c e X S - T i m i n g W e b     x s   s e a r c h   a t t a c k A p p S e c I L 2 0 1 5 _ C r o s s - S i t e - S e a r c h - A t t a c k s _ H e m i L e i b o w i t z X S - S e a r c h   A t t a c k 1 2 b u g C S V G o o g l e c r o s s - o r i g i n   b o o l e a n   q u e s t i o n s T r u e o r   F a l s e c r o s s - o r i g i n   b o o l e a n   q u e s t i o n s H e m i   L e i b o w i t z 2 0 1 5   O W A S P   A p p S e c   G m a i l b u g s . c h r o m i u m . o r g s r c / t h i r d _ p a r t y / p d f i u m /
  S u m m a r y :   T h i s   b u g   e x i s t s C S V S u m m a r y :   T h i s   b u g   d o e s n t   e x i s t C S V   S u m m a r y :   T h i s   b u g   e x i s t s   O R   S u m m a r y :   T h i s   b u g   d o e s n t   e x i s t C S V b u g s u m m a r y   T h i s   b u g   e x i s t s C S V C S V s u m m a r y b u g s u m m a r y   T h i s   b u g   d o e s n t   e x i s t 使 O R T o   a s k   o r   n o t   t o   a s k ? P o C M o n o r a i l M o n o r a i l 退 C h r o m i u m l i n e   n u m b e r     h t t p s : / / b u g s . c h r o m i u m . o r g / p / c h r o m i u m / i s s u e s / d e t a i l ? i d = 7 7 0 1 4 8
X S - S e a r c h   a t t a c k C h r o m i u m M o n o r a i l 线 p a t h / t o / d i r   p a t h / t o / d i r / s u b / d i r 1 C h r o m i u m h t t p s : / / c s . c h r o m i u m . o r g / c h r o m i u m / s r c / 2 O R   s r c / b l i n k   O R   s r c / b u i l d   3 2 C S V s r c / b l i n k C S V s r c / b u i l d 4 U R L 3 C S V r e s p o n s e - l e n g t h   i n f l a t i o n e m p t y   r e s p o n s e f u l l   r e s p o n s e A P I C a c h e   A P I
A P I C a c h e   A P I /   -   g i s t . g i t h u b :   e x p l o i t   c o d e M o n o r a i l C V E C V E - 2 0 1 8 1 0 0 9 9 C V E - 2 0 1 8 1 9 3 3 4     C V E - 2 0 1 8 1 9 3 3 5 9 4 0 1 . 1 * m e d i u m c l o u d s F r e e B u f . C O M
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